Question

find compound interest 12600 for 2 year at 10% per annum​

Answer 1

• Given

• Principal = Rs. 12,600
• Time = 2 years
• Rate = 10%

• To find

• Compound Interest

• Solution

Formula to find Amount - $\leadsto$ $\large{\boxed{\bf{\red{P \bigg[1 + \dfrac{r}{100}\bigg]^n}}}} {\green{\bigstar}}$

where,

• P = Principal
• r = rate%
• n = Time

Substitute the given values,

⇒ $\sf{P \bigg[1 + \dfrac{r}{100}\bigg]^n}$

⇒ $\sf{12600 \bigg[1 + \dfrac{10}{100}\bigg]^2}$

⇒ $\sf{12600 \bigg[1 + \dfrac{1 \not0}{10\not0}\bigg]^2}$

⇒ $\sf{12600 \bigg[1 + \dfrac{1}{10}\bigg]^2}$

⇒ $\sf{12600 \bigg[\dfrac{10 + 1}{10}\bigg]^2}$

⇒ $\sf{12600 \bigg[\dfrac{11}{10}\bigg]^2}$

⇒ $\sf{12600 \times \dfrac{11}{10} \times \dfrac{11}{10}}$

⇒ $\sf{126 \cancel{00} \times \dfrac{11}{1 \not0} \times \dfrac{11}{1 \not0}}$

⇒ Rs. 15246

Amount $\leadsto$ ${\boxed{\bf{\pink{Rs. 15246}}}} {\blue{\bigstar}}$

Formula to find Compound Interest = $\leadsto$ $\large\underline{\boxed{\sf{Amount - Principal}}} {\green{\bigstar}}$

Substitute the given values,

⇒ Rs. 15246 - Rs. 12600

⇒ Rs. 2646

Compound Interest $\leadsto$ $\large{\boxed{\bf{\green{Rs. 2646}}}} {\red{\bigstar}}$