Question

find compound interest and amount if p equals to 36,000 r equals to 20 percent and time equals to 2 years also give amount as well compound interest

give brief explanation and answer me quickly​

Answer 1

Answer:

7920 is the compound

nterest of 36000 of two years

Answer 2

Solution :

$\underline{\bf{Given\::}}}}$

• Principal, (P) = Rs.36000
• Rate, (R) = 20% p.a.
• Time, (n) = 2 years

$\underline{\bf{To\:find\::}}}}$

The compound Interest & amount .

$\underline{\bf{Explanation\::}}}}$

Using formula of the compounded annually :

$\boxed{\bf{Amount=Principal\bigg(1+\frac{R}{100} \bigg)^{n}}}}$

$\longrightarrow\sf{A=36000\bigg(1+\cancel{\dfrac{20}{100}} \bigg)^{2} }\\\\\\\longrightarrow\sf{A=36000\bigg(1+\dfrac{1}{5} \bigg)^{2}}\\\\\\\longrightarrow\sf{A=36000\bigg(\dfrac{5+1}{5} \bigg)^{2}}\\\\\\\longrightarrow\sf{A=36000\bigg(\dfrac{6}{5} \bigg)^{2}}\\\\\\\longrightarrow\sf{A=\cancel{36000} \times \dfrac{6}{\cancel{5}} \times \dfrac{6}{\cancel{5}} }\\\\\\\longrightarrow\sf{A=Rs.(1440\times 36)}\\\\\longrightarrow\bf{A=Rs.51840}$

Now;

We know that compound Interest :

$\longrightarrow\sf{C.I.=Amount-Principal}\\\\\longrightarrow\sf{C.I.=Rs.51840-Rs.36000}\\\\\longrightarrow\bf{C.I.=Rs.15840}$