Math, asked by kimmy69, 9 months ago

find compound interest and amount on ₹12500 for 2years at 8%per annum compounded annually​

Answers

Answered by shrutirajudev21
20

Answer:

Principal (p) = Rs 12500

Rate1 (r) = 15% and Rate2 = 16%

Time (t) = 2 years

By using the formula,

A = P (1 + R1/100 × 1 + R2/100)

= 12500 (1 + 15/100 × 1 + 16/100)

= 12500 (1.15 × 1.16)

= Rs 16675

∴ Amount after two years is Rs 16675.

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Answered by samo2890000
14

Step-by-step explanation:

answer are:

1st year

P= Rs 12500

T= 1 year

R = 8%

SI= P×R×T/100

= 12500×8×1/100 =1000

Amount =12500+1000=13500

2nd year

P=13500

T= 1 year

R= 8%

SI= P×R×T/100

13500×8×1/100= 1080

Amount =13500+1080 = 1215.

there for Compound Intrest is = 1st year amount - 2nd year amount.

13500 - 1215= 12285.

the compound Interst is 12285 .

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