find compound interest and amount on Rs.16000 for 2 years at 2% annual
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Heya ☺
Given that
P = ₹16,000
R = 2 % p.a.
T = 2 years
Solution
A = P(1+R/100)^n
= 16,000(1+2/100)^2
= 16,000(100+2/100)^2
= 16,000(200/100)^2
= 16,000(2)^2
= 16,000 × 4
= ₹64,000
C.I. = A - P
= ₹(64,000 - 16,000)
= ₹48,000
Thanks
Given that
P = ₹16,000
R = 2 % p.a.
T = 2 years
Solution
A = P(1+R/100)^n
= 16,000(1+2/100)^2
= 16,000(100+2/100)^2
= 16,000(200/100)^2
= 16,000(2)^2
= 16,000 × 4
= ₹64,000
C.I. = A - P
= ₹(64,000 - 16,000)
= ₹48,000
Thanks
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