Math, asked by patangepratidnya900, 3 days ago

Find Compound Interest for principal 1500 at the rate 10% p.a. for 1 1/2​

Answers

Answered by manasgupta250693
0

Answer:

CaseI

P=Rs 1500 r=12% p.a t=1 year

Interest =

100

1500×12×1

=Rs180.

∴A=Rs1680.

CaseII

P=Rs 1680 r=12% p.a t=1 year

Interest =

100

1680×12×1

=Rs201.

∴A=Rs1881.60.

CaseIII

P=Rs 1881.60 r=12% p.a t=1 year

Interest =

100

1881.60×12×1

=Rs225.80.

∴A=Rs2107.40.

CaseIV

P=Rs 2107.40 r=12% p.a t=

12

3

=

4

1

years

Interest =

100

2107.40×12

×

4

1

=Rs 63.22.

∴A=Rs 2170.62.

Compound interest is Rs 670.62

Answered by achyuthvdev1
0

Step-by-step explanation:

P=Rs 1500 r=12% p.a t=1 year

Interest =

100

1500×12×1

=Rs180.

∴A=Rs1680.

CaseII

P=Rs 1680 r=12% p.a t=1 year

Interest =

100

1680×12×1

=Rs201.

∴A=Rs1881.60.

CaseIII

P=Rs 1881.60 r=12% p.a t=1 year

Interest =

100

1881.60×12×1

=Rs225.80.

∴A=Rs2107.40.

CaseIV

P=Rs 2107.40 r=12% p.a t=

12

3

=

4

1

years

Interest =

100

2107.40×12

×

4

1

=Rs 63.22.

∴A=Rs 2170.62.

Compound interest is Rs 670.62

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