Question

find compound interest of rupees 12600 for 2 years at 10% per annum compounded annually

Answer 1

Given:-
P=₹12600
T=2
R=10%
Therefore A=?
A=P{1+R/100}^t
=12600{1+10/100}^2
=12600{100/100+10/100}^2
=12600{110/100}^2
=12600{11/10}{11/10}
=126×11×11
=₹15246
Therefore, Amount=₹15246
Therefore,C.I=Amount-Principle
=15246-12600
=₹2646
So,C.I=₹2646(Ans)
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Hope this helps ☺️☺️

Answer 2

Formula : A = P(1 + r)ⁿ where

• A is the total amount after 2 years
• P is the principal amount invested
• r is the rate of interest in decimal
• n is the number years invested

Find the amount earned after 2 years:

A = 12600(1 + 0.1)²

A = Rs 15246

Find the interest:

Interest = 15246 - 12600 = Rs 2646

Answer: The interest is Rs 2646