Find compound interest on ₹11,200 at 35/2 % per annum for 2 years. ( using formula) Please help me out to find the answer
Answers
Answered by
7
11200(1+35/200)²
11200(1+7/40)²
11200(47/40)*(47/40)
(112*47"*47)/16 solve it
11200(1+7/40)²
11200(47/40)*(47/40)
(112*47"*47)/16 solve it
pyara97:
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Anshika Tu Roz kitno Ko Patati he
Answered by
6
Given
Principal =₹11200
rate= 17 1/2%
Rate =35/2%
Time =2yr
As we know Amount=P(1+R/100)^t
=11200(1+35/200)²
=11200x235/200x235/200
=₹15727.32
Compound interest = Amount - principal
Ci=15727.32-11200
Ci=₹4527.32
This is ur ans hope it will help you
Principal =₹11200
rate= 17 1/2%
Rate =35/2%
Time =2yr
As we know Amount=P(1+R/100)^t
=11200(1+35/200)²
=11200x235/200x235/200
=₹15727.32
Compound interest = Amount - principal
Ci=15727.32-11200
Ci=₹4527.32
This is ur ans hope it will help you
wrong he
you took 37 as rate instead 35
no problem :)
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