find compound interest on 12600 for 2 years at 10% per annum annually
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Principal Amount =P= 12600
No.of periods= n = 2 years
Rate of interest Per Annum= i = 10%
Compound interest = P((1+i)^n-1)
= 12600((1+10/100)^2-1)
=12600((1 +0.1)^2-1)
=12600(1.1)^2- 1)
=12600(1.21 -1)
=12600(0.21)
=2646
No.of periods= n = 2 years
Rate of interest Per Annum= i = 10%
Compound interest = P((1+i)^n-1)
= 12600((1+10/100)^2-1)
=12600((1 +0.1)^2-1)
=12600(1.1)^2- 1)
=12600(1.21 -1)
=12600(0.21)
=2646
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