find compound interest on ₹16000 for 3 year at 12% annum compounded annually
Answers
Answered by
3
ci=p[(1+r/100)^n-1]
=16000[(1+12/100)^3-1]
=16000[(1+3/25)^3-1]
=16000[(28/25)^3-1]
=16000[21952/15625-1]
=16000[6327/15625]
=16000×6327/15625
=683316/125
=5466.52(approx)
=16000[(1+12/100)^3-1]
=16000[(1+3/25)^3-1]
=16000[(28/25)^3-1]
=16000[21952/15625-1]
=16000[6327/15625]
=16000×6327/15625
=683316/125
=5466.52(approx)
kishu37:
kya huva
meh 10
in which school
what is your name in school
NDA
you?
bal kiran
NDA KI FULL FORM ??
NOTRE DAME ACADEMY
what is your name in school
Answered by
0
Answer:
₹ 24334
Explanation:
step by step explanation in photo
Attachments:
Similar questions
English,
7 months ago
Accountancy,
7 months ago
History,
1 year ago
Physics,
1 year ago
Math,
1 year ago
Social Sciences,
1 year ago