find compound interest on ₹16000 for 3 year at 12% annum compounded annually
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ci=p[(1+r/100)^n-1]
=16000[(1+12/100)^3-1]
=16000[(1+3/25)^3-1]
=16000[(28/25)^3-1]
=16000[21952/15625-1]
=16000[6327/15625]
=16000×6327/15625
=683316/125
=5466.52(approx)
=16000[(1+12/100)^3-1]
=16000[(1+3/25)^3-1]
=16000[(28/25)^3-1]
=16000[21952/15625-1]
=16000[6327/15625]
=16000×6327/15625
=683316/125
=5466.52(approx)
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