Find compound interest on 2000 for 3 years at 5 % per annum
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Answered by
1
Let the rate of interest be r.
5000[1+ r/100]2 = 5000+253.125
→ [1+r/100]2 = 5253.125/5000
Solving which gives
[1+ r/100]2 = 1681/1600
→ 1+r/100 = 41/40
→ r = 2.5
Therefore, SI = 5000* 2 * 2.5/ 100 = Rs. 250.
5000[1+ r/100]2 = 5000+253.125
→ [1+r/100]2 = 5253.125/5000
Solving which gives
[1+ r/100]2 = 1681/1600
→ 1+r/100 = 41/40
→ r = 2.5
Therefore, SI = 5000* 2 * 2.5/ 100 = Rs. 250.
sabaa:
oh sry i have forgotten its 2000 na
sry i have seen that the question properl
Answered by
2
Answer:
Step-by-step explanation:
P=₹2000
T=3 years
r%=5% p.a.
A=p((1+r)/100)^n
=2000((1+5)/100)^3
=2000×105/100×105/100×105/100
=₹2315.25
CI=A-P
=2312.25-2000
=₹312.25
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