find compound interest on 2500 years2 at10%per annum compound annually
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Answered by
1
1st year interest
P=2500. T=1. R=10%
I=2500×10×1/100=250
Amount=P+I=2750
2nd year interest
P=2750. T=1. R=10%
I=2750×10×1/100=275
Amount=P+I=3025
Compound interest=3025-2500=525
P=2500. T=1. R=10%
I=2500×10×1/100=250
Amount=P+I=2750
2nd year interest
P=2750. T=1. R=10%
I=2750×10×1/100=275
Amount=P+I=3025
Compound interest=3025-2500=525
Answered by
0
1st year interest
P=2500
T=1
R=10%
I=2500×10×1/100=250
Amount=P+I
=2750
2nd year interest
P=2750
T=1
R=10%
I=2750×10×1/100=275
Amount=P+I
=3025
Compound interest=3025-2500
=525
P=2500
T=1
R=10%
I=2500×10×1/100=250
Amount=P+I
=2750
2nd year interest
P=2750
T=1
R=10%
I=2750×10×1/100=275
Amount=P+I
=3025
Compound interest=3025-2500
=525
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