Question

Find compound interest on ₹4500 for 9 months at 4% per annum compound quarterly

please take a picture of answer
and give me
answer is 136.35​​

Answer 1

P = 4500

T = 9 months

$= \frac{9}{12}$

$= \frac{3}{4}$

R = 4%

● Compound Quarterly

$a \: = \: p \: \times {1 + \frac{r}{4 \times 100} }^{4n}$

$= \: 4500 \: \times {1 + \frac{4}{4 \times 100} }^{4 \times \frac{3}{4} }$

$= \: 4500 \: \times { \frac{400 + 4}{400} }^{3}$

$= \: 4500 \: \times { \frac{404}{400} } \times { \frac{404}{400} } \times { \frac{404}{400} }$

= 18407.7045

CI = A - P

= 18407.7045 - 4500

= 13907.7045