Math, asked by kingbhavik980, 12 hours ago

find compound interest on Rs 10,000 at 8% for 2 years.​

Answers

Answered by Anonymous
67

Given :

  • Principal = Rs.10000
  • Rate = 8 %
  • Time = 2 years

\rule{200pt}{3pt}

To Find :

  • Compound Interest = ?

\rule{200pt}{3pt}

Solution :

~ Formula Used :

\large{\color{darkblue}{\bigstar}} \: \: {\underline{\boxed{\orange{\sf{ C.I = P \bigg\{ 1 + \dfrac{R}{100} \bigg\} ^T - P }}}}}

Where :

  • ➺ C.I = Compound Interest
  • ➺ P = Principal
  • ➺ R = Rate
  • ➺ T = Time

\qquad{━━━━━━━━━━━━━━━━━━━━━━━}

~ Calculating the Compound Interest :

{:\implies{\qquad{\sf{ C.I = P \bigg\{ 1 + \dfrac{R}{100} \bigg\} ^T - P }}}} \\ \\ \ {:\implies{\qquad{\sf{ C.I = 10000 \bigg\{ 1 + \dfrac{8}{100} \bigg\} ^2 - 10000 }}}} \\ \\ \ {:\implies{\qquad{\sf{ C.I = 10000 \bigg\{ 1 + \cancel\dfrac{8}{100} \bigg\} ^2 - 10000 }}}} \\ \\ \ {:\implies{\qquad{\sf{ C.I = 10000 \bigg\{ 1 + 0.08 \bigg\} ^2 - 10000 }}}} \\ \\ \ {:\implies{\qquad{\sf{ C.I = 10000 \bigg\{  1.08 \bigg\} ^2 - 10000 }}}} \\ \\ \ {:\implies{\qquad{\sf{ C.I = 10000 \times 1.08 \times 1.08 - 10000 }}}} \\ \\ \ {:\implies{\qquad{\sf{ C.I = 11664 - 10000 }}}} \\ \\ \ {\qquad{\textsf{ Compound Interest = {\pink{\bf{ ₹ \: 1164 }}}}}}

\qquad{━━━━━━━━━━━━━━━━━━━━━━━}

~ Therefore :

❝ Compound Interest on this amount for at 8 % for 2 years is 1164 . ❞

 \\ {\pink{\underline{\green{\rule{300pt}{9pt}}}}}

Similar questions