Question

find compound interest on rs 2000 at 10per per annum for 2 years .

solve it fast plz .
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Answer 1

$\sf{\bold{\green{\underline{\underline{Given}}}}}$

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Principle = Rs. 200

Rate = 10%

Time = 2 years

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$\sf{\bold{\green{\underline{\underline{To\:Find}}}}}$

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Compound Interest = ??

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$\sf{\bold{\green{\underline{\underline{Solution}}}}}$

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$\sf{\red{\boxed{\bold{Amount = Principle \bigg\lgroup 1 + \dfrac{r}{100}\bigg\rgroup ^{time}}}}}$

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$\sf :\implies\:{\bold{ Amount = 200 \bigg\lgroup 1 + \dfrac{10}{100}\bigg\rgroup^{2}}}$

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$\sf :\implies\:{\bold{ Amount = 200 \bigg\lgroup 1 + \dfrac{1}{10}\bigg\rgroup^{2}}}$

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$\sf :\implies\:{\bold{ Amount = 200 \bigg\lgroup \dfrac{10 + 1 }{10}\bigg\rgroup^{2}}}$

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$\sf :\implies\:{\bold{ Amount = 200 \bigg\lgroup \dfrac{11}{10}\bigg\rgroup^{2}}}$

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$\sf :\implies\:{\bold{ Amount = 200 \times\dfrac{11}{10}\times \dfrac{11}{10}}}$

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$\sf :\implies\:{\bold{ Amount = 20 \times\dfrac{11}{10}\times {11}}}$

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$\sf :\implies\:{\bold{ Amount = 2\times{11}\times{11}}}$

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$\sf :\implies\:{\bold{ Amount = 2\times 121}}$

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$\sf :\implies\:{\bold{ Amount = Rs. 242}}$

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$\sf{\red{\boxed{\bold{CI = Amount - Principle}}}}$

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$\sf :\implies\:{\bold{CI = Rs. 242 - Rs. 200}}$

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$\sf :\implies\:{\bold{CI = Rs. 42}}$

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$\sf{\bold{\green{\underline{\underline{Answer}}}}}$

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Rs. 200 will earn Rs. 42 as Compound Interest in 2 years at 10% per annum

Answer 2

Step-by-step explanation:

Step-by-step explanation:

Given Equation:-

⠀⠀⠀⠀ $\sf{\bigg[ \dfrac{5 {x}^{2} - 10}{12 } \bigg] }$

To find:-

value of x

Solution:-

use factor theorem

take the value of equation =0

$\\\qquad\quad\displaystyle\sf{:}\longrightarrow \left [\dfrac {5x^2-10}{12}\right]=0$

$\\\qquad\quad\displaystyle\sf{:}\longrightarrow \dfrac {5x^2-10}{12}=0$

using cross multiplication

$\\\qquad\quad\displaystyle\sf{:}\longrightarrow 5x^2-10=0$

$\\\qquad\quad\displaystyle\sf{:}\longrightarrow 5x^2=10$

$\\\qquad\quad\displaystyle\sf{:}\longrightarrow x^2=\dfrac {10}{5}$

$\\\qquad\quad\displaystyle\sf{:}\longrightarrow x^2=2$

$\\\qquad\quad\displaystyle\sf{:}\longrightarrow x=\sqrt {2}$

$\\\\\therefore\sf x=\sqrt {2}.$