Question

find compound interest on rs 4000 for 2 1/2years at a rate of 10%

Answer 1

A= p(1+r/100)to the power n
a= 4000(11/10)(11/10)
a=4000(121/100)

Answer 2

Answer:

For 2 years = Compound Interest

For 1/2 years= Simple Interest

×$A=P * (1 + \frac{R}{100} )^{2} \\\\A=4000 * (1 + \frac{12}{100} )^{2}\\\\A=4000* (1 + \frac{3}{25} )^{2}\\\\A=4000*\frac{28}{25} *\frac{28}{25}$