Question

find compound interest on ruppe 11,200 at 17 1 by 2 % per annum for two years.​

Answer 1

The compound interest on ruppe 11,200 at 17 1 by 2 % per annum for two years is  Rs. 4263.

Step-by-step explanation:

Required Formula:

• Compound Interest, C.I. = P [(1 + $\frac{R}{100}$)² - 1]

Principal, P = Rs. 11200

The rate of interest, R = 17$\frac{1}{2}$% p.a. = $\frac{35}{2}$%

Time period, n = 2 years

Now, substituting the given values in the above formula, we get

C.I. = 11200 [(1+$\frac{\frac{35}{2}}{100}$)² - 1]

⇒ C.I. = 11200 [($\frac{47}{40}$)² - 1]

⇒ C.I. = 11200 [($\frac{2209}{1600}$) - 1]

⇒ C.I. = 11200 * $\frac{609}{1600}$

⇒ C.I. = 7 * 609

⇒ C.I. = Rs. 4263

Thus, the compound interest is Rs. 4263.

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C.i. and s.i. for a certain sum at a certain rate of interest for 2 years are rs. 220 and rs. 200. find the principal amount.

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The compound interest on a certain sum for 2 years is rs. 756 and simple interest is rs. 720. if the sum is invested such that the si is rs. 900 and the number of years is equal to the rate percent per annum, find the rate percent.

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Answer 2

Step-by-step explanation:

p = 11200

r = 17

1/2 =35/7

t= 2 years

amount = p + r/100

=11200(1+35/2×100)

=11200(1+35/200)

=11200×47/40+47/40

=15463rs

c.i= amount –principal

=rs 15463–11200

=4263...

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