find compound interest on sum of Rs12000 at the rate of 8% for 3 years compounded annually pls answer it is urgent
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Answer:
C.I = 989.18
Step-by-step explanation:
A = P (1+r/400)^4n
=12000 (1+8/400)^4×1
=12000 (1+1/50)^4
=12000×51/50×51/50×51/50×51/50
=12×51×51×51×51/5×5×5×50
=6×6,765,201/5×5×5×25
=40,591,206/3125
A=12,989.18592
therefore, C.I. = A - P
= 12,989.18592 - 12000
C.I = 989.18
pls mark as brainliest answer
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