Find compound interest on the sum of Rs 15,000 at the rate 12% p.a. for 3 years
Rajesh1Nivadh:
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Answered by
29
HELLO!!
ANSWER:
Compound interest = ₹6073.92
EXPLANATION:
GIVEN:
Principal (P) = ₹15000
Rate of interest (r) = 12% p.a.
Time (n) = 3 years
TO FIND:
Compound interest
SOLUTION:
AMOUNT (A)= P ( 1 + r/100)³
A= 15000 (1 + 12/100)³
A= 15000( 1 + 0.12)³
A= 15000 (1.12)³
A= 15000 (1.404928)
A= ₹21073.92
COMPOUND INTEREST (CI)= A-P
CI = ₹21073.92 - 15000
CI = ₹6073.92
HOPE IT HELPS YOU!!
ANSWER:
Compound interest = ₹6073.92
EXPLANATION:
GIVEN:
Principal (P) = ₹15000
Rate of interest (r) = 12% p.a.
Time (n) = 3 years
TO FIND:
Compound interest
SOLUTION:
AMOUNT (A)= P ( 1 + r/100)³
A= 15000 (1 + 12/100)³
A= 15000( 1 + 0.12)³
A= 15000 (1.12)³
A= 15000 (1.404928)
A= ₹21073.92
COMPOUND INTEREST (CI)= A-P
CI = ₹21073.92 - 15000
CI = ₹6073.92
HOPE IT HELPS YOU!!
Answered by
13
R=12%p.a
p=15000
t=3year
A=p(1+R/100)^t
A=15000(1+12/100)^3
A=15000(112/100)^3
A=(15000×112×112×112)/100×100×100
A=(15×112×112×112)/1000
A=21073.92rs
ci=A-p
ci=21073.92-15000
ci=6073.92rs
p=15000
t=3year
A=p(1+R/100)^t
A=15000(1+12/100)^3
A=15000(112/100)^3
A=(15000×112×112×112)/100×100×100
A=(15×112×112×112)/1000
A=21073.92rs
ci=A-p
ci=21073.92-15000
ci=6073.92rs
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