Question

Find compound interest on the sum of rupee 3000 for 1whole 1/2 year at 8 % per annum compound yearly



please do language also​

Answer 1

Answer:

We know the formula,

Where,

A= total amount

P= principal or amount of money deposited,

r= annual interest rate

n= number of times compounded per year

t= time in years

Given:

P= Rs. 3000,r=8%,n=4 and t=2 years

A=3000(1+

4

0.08

)

4×2

A=3000×1.02

8

A=3000×1.171659

A= Rs. 3514.98

To find interest we use formula A=P+I, since A=3514.98 and P=3000, we have:

A=P+I

⇒3514.98=3000+I

⇒I=3514.98−3000=514.98

Interest, I= Rs. 514.98

Hope it helps you ✌️

Step-by-step explanation:

please make me brainliest

Answer 2

Step-by-step explanation:

Given:-

the sum of rupee 3000 for 1whole 1/2 year at

8 % per annum compound yearly .

To find:-

Find compound interest .

Using formula:-

If Principle P , Number of times compound interest to be calculated n, Rate of interest R then the compound Amount=P(1+R/100)^n

Solution:-

Principle amount=(P)=Rs. 3000

Rate of interest (R)=8%

Compound interest is calculated annually

Time(T)=1 1/2 year

Now we know that

A=3000(1+8/100)(1+(1/2)8/100)

=>A=3000(108/100)(1+4/100)

=>A=3000(27/25)(26/25)

=>A=(3000×27×26)/(25×25)

=>A=120×27×26/25

=>A=24×27×26/5

=>A=16848/5

=>A=3369.6

Amount =Rs. 3369.6

Compound Interest=Amount-Principle

=>CI=3369.6-3000

=>CI=Rs. 369.6

Answer:-

The Compound Interest for the given problem is Rs. 369.6