Math, asked by dblc7371, 10 months ago

Find compound interest to the nearest rupee on rs 7500 for 2 years 4 months at 12% compounded anually

Answers

Answered by haridasan85

5

Answer:

A = 7500 (I +12/100) 2 (1 +4/100)

= 7500x(112/i00)^2 (104/100)

= 9784.32

Cl=9784.32-7500 = Rs.2284.32

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