Question

find compound interest when the principal is Rs. 12000, the time period is 1 year and the rate is 8% per annum compounded half yearly​

Answer 1

$\huge\bold{\mathtt{\purple{✍︎A{\pink{N{\green{S{\blue{W{\red{E{\orange{R✍︎}}}}}}}}}}}}}$$\huge \Rightarrow$

$\Large \bold \red{Solution}\Rightarrow$

Note:

A = Amount

P = Principal

N = No of years

R = Rate

$\bold {Given:}$

Principal = 12000

Time = 1 year

Rate = 8%

$\bold {To\:Find:}$

$\large \Rightarrow$$A=P (1 \large \frac {R}{100}{ )}^{n}$

$\large \Rightarrow$$A=12000\Large(1 \frac {8}{100}{) }^{1}$

$\large \Rightarrow$$A=12000\Large ( \frac {100+8}{100}{ )}^{1}$

$\large \Rightarrow$$A=12000 ( \frac {108}{100}{)}^{1}$

$\large \Rightarrow$$A=\Large ( \frac {12000×108×108}{100×100}{)}$

$\large \Rightarrow$$A = \sf \dfrac{\cancel{12000}{\cancel{\:×108}{\:×108}}}{\cancel{100}{\cancel{×100}}}$

$\large \Rightarrow$$A= 120×1.8×108$

$\large \Rightarrow$$A=13996.8$

.

.

Compound Interest = Amount - Principal

Compound Interest = 13996.8 - 12000

Compound Interest = 1996.8

$\Large \bold \blue{Ans}\Rightarrow$

The Compound Interest is 1996.8 Rs.