Question

Find compound intrest and Amount

Find the CI, if Rs 5000 was invested for 2 years at 10% p.a. compounded half-yearly?

Answer 1

Answer:

Step-by-step explanation:

Given:

Principle = p = 5,000

Rate of interest  = 10%

Time = 2 yrs

To find:

Compound interest and Amount

Equation used:

$\boxed{CI = p(1+i)^n-1}$

Solution:

$CI = 5000(1+0.05)^4-1$

$CI = 5000(1.05)^4-1$

$CI = 5000(0.2155)$

$CI = 1077$

Thus the compound interest for 5000 at 10% for 2 yrs compounded semi-annually is 1077

$\boxed{\green{Amt} = \blue{Principle} + \red{Interest}}$

Amt = 5,000 + 1077

Amt = 6,077

Answer 2

QUESTION:-

find the CI, if Rs 5000 was invested for 2 years at 10% p.a. compounded half - yearly ?

GIVEN:-

• principal= Rs 5000
• rate = 10 %
• time = 2 yrs

TO FIND:-

• Compound interest ( CI) = ?
• Amount = ?

FORMULA'S USED:-

• compound interest = amount - principal
• Amount(A) = P ×$1 +\frac{r}{100} ^{n}$

SOLUTION:-

A = $P* (1\frac{r}{100} )^{n}$

⇒ A = 5000 × $(1+\frac{10}{100} )^{2}$

⇒ A =  5000 ×$(\frac{11}{10} ) \sqx^{2}$

⇒ A =  6050

Now, CI = 6050-5000

             = 1050

hence, compound interest is Rs 1050

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hope it helps :D