Math, asked by josephjames950p5w9s8, 1 year ago

find compound intrest on 8000 for 1 year at 9% per annum compounded half yearly


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Answers

Answered by vishakha24
72
p=8000
t=1 year =2half year
r=9%pa =4.5%half yearly
si for 1st half year=p×r×t/100
=(8000×4.5×1)/100
=8×45
=360
amt for 1st year= 8360
p for 2nd half year= 8360
si for 2nd half year=8360×4.5×1/100
=376.2
amt for 2nd half year= 8360+376.2
=8736.2
ci= A-p
= 8736.2-8000
=736.2ans.

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Answered by sourasghotekar123
0

Answer:

Compound interest on 8000 for 1 year at 9% per annum compounded half yearly is 8736.2

Step-by-step explanation:

p = 8000 t = 1 year = 2half year

r = 9%pa = 4.5%half yearly 

si for first half year = prt/100 

= 9%pa =4.5%half yearly si for first half year = prt/100 

= (80004.51)/100 =845 = 360 amt for first year = 8360 p 

for second half year = 8360 si 

for second half year = 83604.51/100 =376.2 amt 

for second half year = 8360+376.2 

= 8736.2

  • Compound interest is calculated by multiplying the initial principal amount by one and adding the annual interest rate multiplied by the number of compound periods minus one.
  • The loan's total initial amount is then deducted from the resulting value.
  • The compound interest formula is CI = P(1 + r/100)n - P.
  • The amount is calculated in this formula, and the principal is subtracted to obtain the compound interest value.

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