find compound intrest on 8000 for 1 year at 9% per annum compounded half yearly
BhaskarGupta06:
hlo may yhis help u
Answers
Answered by
72
p=8000
t=1 year =2half year
r=9%pa =4.5%half yearly
si for 1st half year=p×r×t/100
=(8000×4.5×1)/100
=8×45
=360
amt for 1st year= 8360
p for 2nd half year= 8360
si for 2nd half year=8360×4.5×1/100
=376.2
amt for 2nd half year= 8360+376.2
=8736.2
ci= A-p
= 8736.2-8000
=736.2ans.
Hope it helps you.
t=1 year =2half year
r=9%pa =4.5%half yearly
si for 1st half year=p×r×t/100
=(8000×4.5×1)/100
=8×45
=360
amt for 1st year= 8360
p for 2nd half year= 8360
si for 2nd half year=8360×4.5×1/100
=376.2
amt for 2nd half year= 8360+376.2
=8736.2
ci= A-p
= 8736.2-8000
=736.2ans.
Hope it helps you.
Answered by
0
Answer:
Compound interest on 8000 for 1 year at 9% per annum compounded half yearly is 8736.2
Step-by-step explanation:
p = 8000 t = 1 year = 2half year
r = 9%pa = 4.5%half yearly
si for first half year = prt/100
= 9%pa =4.5%half yearly si for first half year = prt/100
= (80004.51)/100 =845 = 360 amt for first year = 8360 p
for second half year = 8360 si
for second half year = 83604.51/100 =376.2 amt
for second half year = 8360+376.2
= 8736.2
- Compound interest is calculated by multiplying the initial principal amount by one and adding the annual interest rate multiplied by the number of compound periods minus one.
- The loan's total initial amount is then deducted from the resulting value.
- The compound interest formula is CI = P(1 + r/100)n - P.
- The amount is calculated in this formula, and the principal is subtracted to obtain the compound interest value.
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