Question

find compound Intrest on rs 5000 at 12%pa if 1 1/2 years if interstitial is compounded half year​

Answer 1

Answer :-

Given :-

• Principal, P = Rs. 5000
• Rate of interest, R = 12%
• Time = 1.5 years

To Find :-

• Compound interest invested half yearly

Solution :-

We know that,

$\boxed{\sf A = P \Big( 1 + \frac{\frac{R}{2}}{100}\Big)^{2n}}$

Substituting the values :-

➩ $\sf A = 5000 \times \Big( 1 + \frac{\frac{12}{2}}{100}\Big)^{2 \times 1.5}$

➩ $\sf A = 5000 \times \Big(1 + \frac{6}{100}\Big)^{3}$

➩ $\sf A = 5000 \times \Big(\frac{53}{50}\Big)^{3}$

➩ $\sf A = 5 \cancel{000} \times \frac{148,877}{125 \cancel{000}}$

➩ $\sf A = \cancel5 \times \frac{148,877}{\cancel{125}}$

➩ $\sf A = \frac{148,877}{25}$

➩ $\sf A = 5,955.08$

⠀

⠀

Compound interest = Amount - Principal

= 5,955.08 - 5000

= 955.08

⠀

⠀

Compound interest = ₹ 955.08