Math, asked by anuragdwivedi4333, 1 month ago

find compound intrest on ru.12500 for 2 year at 12% per annum compounded annually​

Answers

Answered by prabhas24480
4

\huge \fbox \purple{❥ Answer}

1st year

P= Rs 12500

T= 1 year

R = 8%

SI= P×R×T/100

= 12500×8×1/100 =1000

Amount =12500+1000=13500

2nd year

P=13500

T= 1 year

R= 8%

SI= P×R×T/100

13500×8×1/100= 1080

Amount =13500+1080 = 1215.

there for Compound Intrest is = 1st year amount - 2nd year amount.

13500 - 1215= 12285.

the compound Interst is 12285 .

Answered by UniqueBabe
28

Answer:

1st year

P= Rs 12500

T= 1 year

R = 8%

SI= P×R×T/100

= 12500×8×1/100 =1000

Amount =12500+1000=13500

2nd year

P=13500

T= 1 year

R= 8%

SI= P×R×T/100

13500×8×1/100= 1080

Amount =13500+1080 = 1215.

there for Compound Intrest is = 1st year amount - 2nd year amount.

13500 - 1215= 12285.

the compound Interst is 12285 .

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