Question

Find+conductivity+of+gold+wire+of+length+10cm+and+having+cross-sectional+area+of+10^-4+and+resistance+of+0.25ohms

Answer 1

Explanation:

R=ρl/a

1/ρ= conductivity -k

k=A/RL

k=10^-4×10/0 .25

k=4×10^-3

Answer 2

Answer:

4000

Explanation:

conductivity(σ)= 1/resistivity

R=ρl/a where ρ⇒resistivity

.25= ρ.1/$10^{-4}$ => ρ=.25×$10^{-3}$

∴σ=4000