find conjugate and modulus of (1 + i ) (2 +i ) ÷3+i
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(1+2i)(2−i)
(3−2i)(2+3i)
=
2−i+4i+2
6+9i−4i+6
=
4+3i
12+5i
=
16−9
(12+5i)(4−3i)
=
5
48−36i+20i+15
=
5
63−16i
The conjugate is
5
63+16i
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