find conjugate of 1/√2i+3/√2
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Answered by
1
Answer:
3−2i)(2+3i)
=
2−i+4i+2
6+9i−4i+6
=
4+3i
12+5i
=
16−9
(12+5i)(4−3i)
=
5
48−36i+20i+15
=
5
63−16i
The conjugate is
5
63+16i
Step-by-step explanation:
3−2i)(2+3i)
=
2−i+4i+2
6+9i−4i+6
=
4+3i
12+5i
=
16−9
(12+5i)(4−3i)
=
5
48−36i+20i+15
=
5
63−16i
The conjugate is
5
63+16i
Answered by
0
Answer:
Z= 1/√2 i. + 3/√2
= i +3/√2
= √2i + 3√2/2
= 3√2 √2i/2
=. 3√2/2 + √2/2i
conjugate = 3√2/2. - √2/2i
Step-by-step explanation:
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