Question

find conjugate of (3-2i)/1+2i​

Answer 1

Answer:

Step-by-step explanation:

3−2i)(2+3i)

​

=  

2−i+4i+2

6+9i−4i+6

​

 

=  

4+3i

12+5i

​

 

=  

16−9

(12+5i)(4−3i)

​

 

=  

5

48−36i+20i+15

​

 

=  

5

63−16i

​

 

The conjugate is  

5

63+16i

​

Answer 2

Answer:

Conjugate of (3-2i)/(1 + 2i)

Step-by-step explanation:

Let,

complex number Z = a + ib

Conjugate of Z = a-ib

Given,

= $\frac{3-2i}{1+ 2i}$

= $\frac{3-2i}{1 + 2i} *\frac{1-2i}{1-2i}$

= $\frac{(3-2i)(1-2i)}{(1-2i)(1+2i)}$

= $\frac{3 -4-2i-6i}{1 + 4}$

Z = $\frac{-1-8i}{5}$

Final answer,

conjugate of Z = $\frac{-1}{5} +\frac{8i}{5}$