Find conjugate of z= (1+i) (2+i) (3 +3i)
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Step-by-step explanation:
= (1+i)(2+i)(3+3i)
= 2+i+2i+i^2(3+3i)
= 2+3i+i^2(3+3i). [ i^2= -1 ]
= 2+3i-1(3+3i)
= 1+3i(3+3i)
= 3+3i+9i+9i^2. [ 9i^2 = -9 ]
= 3 + 12i - 9
= (-6) + 12i
The conjugate of -6 + 12i is -6 - 12i
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