Question

Find consecutive positive integers of 99​​

Answer 1

Let the 2 consecutive odd integers be n and n+2.

n(n + 2) = 99

Solve for n.

n2 + 2n - 99 = 0

(n + 11)(n - 9) = 0

we get Two solutions:

n = -11

n + 2 = -9

and

n=9

n + 2 = 11

Answer 2

Answer:

9 and 11 these are the consecutive positive integers of 99