Question

find
consecutive
the fourth renten of the
parallelogram
whose
vertices are (2,4,-1), (3,6,-1) and (4,5,1).

​

Answer 1

Step-by-step explanation:

A(8,4)B(5,7)C(−1,1).

Let D(x,y)

m.p of BD = m.p of AC

( 5+x/2 ,7+y/2)=(8-1/2,4+1/2)

(5+x/2,7+y/2) = 7/2,5/2

5+x/2=7/2

5+x=7

x=2

7+y/2= 5/2

7+y=5

y=−2

∴D(2,−2)

I hope this answer will help you