Question

find coordinates of a point whose distance from (3,5) is 5 inits and from (0,1) is 10 units

Answer 1

let the line formed by the coordinates be A(3,5) and B(0,1)

let the point be C(p,q)

distance of the point A from point C is 5 units and distance of point B from point C is 10 units so the line line is getting divided into 5:10 or 1:2 .

m1= 1

m2= 2

x1= 3

x2= 0

y1= 5

y2= 1

now by applying section formula

we get

p =( 1x0+2x3) / 3    and

q = (1x1+2x5) / 3

from here we get p= 2 and q= 11/3

therefore the point becomes (2,11/3)

this is the section formula that i used