Find cos 15 using cos (a-b) =cosa cos b+sina sin b
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Hey mate Your answer is here
Cos15°
can be written as
cos(45-30)°
so we can use
cos(a-b)=CosACosB+SinASinB. as given
Therefore
Cos(45-30)°
=Cos45°Cos30°+Sin45°Sin30°
=(1/√2)(√3/2)+(1/√2)(1/2)
=(√3/2√2) + (1/2√2)
= (√3+1)
2√2
Thank you
Regards ☺️
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