find cos (π/2+ theta)+cos(3π/2+ theta)+cos(5π/2+theta)+cos(7π/2+theta) upto 2021 terms
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Answer:
cos (π/2 + θ) = -sin θ
cos (3π/2 + θ) = sin θ
cos (5π/2 + θ) = -sin θ ..
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The terms are all identical, apart from alternating sign.
There is an odd number of terms; and each adjacent pair sums to zero.
So the sum of 2021 terms = the first (or last) term = -sin θ .
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