find cos^4B-sin^4B ?
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cos⁴B - sin⁴B
(cos²B)²- (sin²B)² (by identity)
(cos²B - sin²B) (sin²B + cos²B)
cos²B - sin²B is the answer
(cos²B)²- (sin²B)² (by identity)
(cos²B - sin²B) (sin²B + cos²B)
cos²B - sin²B is the answer
Answered by
4
cos^4B - sin^4 B
= (co²B+sin²B)(cos²B - sin²B) [a²-b²= (a+b)(a-b)
1(cos²B - sin²B) [sin²B + cos²B= 1]
= cos²B - sin²B
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= (co²B+sin²B)(cos²B - sin²B) [a²-b²= (a+b)(a-b)
1(cos²B - sin²B) [sin²B + cos²B= 1]
= cos²B - sin²B
Hope it helps you
Please mark it BRAINLIEST
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