Math, asked by 3altafsiddique, 6 months ago

find: cos (70°+Q)cos(10°+Q)+sin(70°+Q)sin(10°+Q)

Answers

Answered by swayamg78

1

Answer:

Step-by-step explanation:

IT IS IN THE FORM COSACOSB + SINASINB=COS(A-B)

COS(70+Q-10-Q)

COS(60)

1/2

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