find cos 90+x if cosx = 4/5 if x lie between 0to 90
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cos(90 + x) = - sinx
cos x= 4/5
sin x= √1-16/25 = √9/25 = 3/5
cos(90+ x) = - 3/5,
or
cos x= 4/5,
as we know cos 37 = 4/5
x= 37
cos( 90 + 37) = - sin 37
and sin 37 = 3/5
= -3/5
or cos90 cos37 - sin90 sin37
cos90= 0
So -sin90 sin37
-sin37= -3/5
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3
ur answer .....tell me if its correct..
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sheenamchopra8:
correct
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