find (cos a - sin a)^2 + (cos a + sin a)^2
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Answered by
1
It will be
=cosa^2+sina^2-2sinacosa+cosa^2+sina^2+2sinacosa
=2sina^2+2cosa^2
=2
=cosa^2+sina^2-2sinacosa+cosa^2+sina^2+2sinacosa
=2sina^2+2cosa^2
=2
Answered by
2
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= ( cos a - sin a ) ^ 2 + ( cos a + sin a ) ^ 2
=cos ^ 2a + sin ^ 2a - 2 * cos a * sin a + cos ^2a+ sin ^ 2 a + 2 * cos a * sin a
We know that, cos ^ 2 a + sin ^ 2 a = 1
= 1 + 1
= 2
= ( cos a - sin a ) ^ 2 + ( cos a + sin a ) ^ 2
=cos ^ 2a + sin ^ 2a - 2 * cos a * sin a + cos ^2a+ sin ^ 2 a + 2 * cos a * sin a
We know that, cos ^ 2 a + sin ^ 2 a = 1
= 1 + 1
= 2
Anonymous:
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