Question

Find cos θ, if tan θ = 2/3. given 3pi/2 < θ < 2pi

Answer 1

Answer:

cos x = 3/(√13)

Step-by-step explanation:

sec²x= tan²x+1

sec²x= 13/9

cos²x= 9/13 [sec(x)= 1/(cosx)]

now since x is in 4th quadrant, cos x is positive

therefore cos x = 3/(√13)