Find ∫(cos²2x − sin²2x)dx
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it is a question of math not Indian language....
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1.∫(cos²2x − sin²2x)dx is sin4x/4+c
2.To solve this we know a formula
consider α as any angle
ie cos²α-sin²α=cos 2α (by trigonometry )
so
3.cos²2x-sin²2x=cos2×2x(considering α=2x in above formula)
cos²2x-sin²2x=cos4x
4.we know that ∫cosx=sinx+c
so ∫cos 4x=sin4x/4+c
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