Question

Find cosA and tanA if sinA=2/3

Answer 1

Hope it's clear..........

Answer 2

Step-by-step explanation:

sin A=2/3

(sinA)^2=(2/3)^2

(sinA)^2=4/9

As_

(sinA)^2+(cosA)^2=1

4/9+(cosA)^2=1

(cosA)^2=1-4/9

=5/9

cosA=root(5/9)

cosA=(root5)/3

but I dont know the second part

hope it helps

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