Question

Find cosec 30 degree and cos 60 degree geometrically

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Consider a triangle with each side equal to 2a.

<A=<B=<C=60°

Draw AD perpendicular to BC.

∆BDA~=~∆CDA by RHS.

So, BD= CD

and, <BAD=<CAD =30° by CPCT.

By Pythagoras theorem,

AD=√3a

In ∆BDA,

cosec 30°=AB/BD =2a/a =2

and, cos 60°=BD/AB=a/2a=1/2

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