Question

find cosec 60°,sec 60° and cot 60°

Answer 1

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Answer 2

Answer:

i) Cosec60° = $\frac{2}{\sqrt{3}}$

ii)Sec60° = = $2$

iii)cot60° = = $\frac{1}{\sqrt{3}}$

Explanation:

i)Value of Cosec60°

= $\frac{1}{sin60}$

= $\frac{1}{\frac{\sqrt{3}}{2}}$

= $1\times\frac{2}{\sqrt{3}}$

= $\frac{2}{\sqrt{3}}$

ii) Value sec60°

=$\frac{1}{cos60}$

= $\frac{1}{\frac{1}{2}}$

= $1\times\frac{2}{1}$

= $2$

iii) Value of cot60°

= $\frac{cos60}{sin60}$

= $\frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}$

=$\frac{1}{2}\times\frac{2}{\sqrt{3}}$

= $\frac{1}{\sqrt{3}}$

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