Question

FIND. COSEC THETA ..

Sec THETA +tan theta =p




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Answer 1

Given:-

$\longmapsto \sf sec \: θ + tan \: θ = p$

Solution:-

$: \longrightarrow \sf \: \frac{1}{cos \:θ} + \frac{sin \:θ }{cos \: θ} = p$

$: \longrightarrow \sf \: \frac{1 + sin \: θ}{cos \:θ } = p$

$: \longrightarrow \sf \: 1 + sin \: θ = p \times cos \: θ$

$: \longrightarrow \sf \: sin \: θ = p \times cos \: θ - 1$

$: \longrightarrow \sf \: \frac{1}{sin \: θ} = \frac{1}{p \times cos \:θ - 1 }$

$:\longrightarrow \red{\sf \: cosec \: θ = \frac{1}{p \times cos \:θ - 1 } }$

Answer 2

Question:-

FIND. COSEC THETA.

Sec THETA +tan theta =p

Correct answer:-

➙ (Refer to the above attachment).

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