find cosecO when sinO=√3/2
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Answered by
1
Step-by-step explanation:
Sin theta =√3/2= p/h
AB²+BC²=AC²
=>(√3)²+BC²=2²
=>BC²=4-3
=>BC=1
b=1 , p=√3, h=2
cos theta =b/h=1/2
tan theta= p/b=√3/1
cosec theta =h/p=2/√3
sec theta =h/b=2/1
cot theta=b/p=1/√3
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Answered by
1
Step-by-step explanation:
GIVEN,
sinO=root3/2
since root3/2=sin60
sinO=sin60
O=60
then
cosecO=cosec60=2/root3
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