Math, asked by pushpa3661, 10 months ago

Find CSA and TSA of cylinder whose base radius 14 cm and height 21 cm

Frnds plzz answer it

Answers

Answered by bhanuprakashreddy23

Step-by-step explanation:

CSA of cylinder=2πrh=2(22/7)(14)(21)=1848sqcm

TSA of cylinder=2πrh+2πr^2=1848+2(22/7)(14)^2

=1848+1232=3080

Answered by Mihir1001

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$Answer:$

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$Step-by-step-explaination:$

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let,

base radius, r = 14 cm.

and,

height, h = 21 cm.

Therefore,

CSA of the cylinder

$= 2\pirh$

$= 2 \times \frac{22}{7} \times 14 \: cm \: \times 21 \: cm$

$= 2 \times \frac{22}{7} \times 7 \times 2 \times 21 \: {cm}^{2}$

$= 2 \times 2 \times 21 \times 22 \: {cm}^{2}$

$= 4 \times 482 \: {cm}^{2}$

$= 1928 \: {cm}^{2}$

and,

TSA of the cylinder

$= 2\pirh + \pi {r}^{2}$

$= 1928 \: {cm}^{2} + \frac{22}{7} \times 14 \: cm \times 14 \: cm$

$= 1928 \: {cm}^{2} + 22 \times 2 \times 14 \: {cm}^{2}$

$= 1928 + 616 \: {cm}^{2}$

$= 2544 \: {cm}^{2}$

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