Question

find cube root of -1728

Answer 1

Answer:

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●By using prime factorisation process,

●LCM of 1728=2×2×2×2×2×2×3×3×3

So,here we go

$\begin{gathered} \sqrt{1728} = \sqrt{2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 3 \times 3 \times 3 } \\ = \sqrt{ {2}^{3} \times {2}^{3} \times {3}^{3} } \\ = 2 \times 2 \times 3 \\ = 12\end{gathered}$

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Answer 2

●By using prime factorisation process,

●LCM of 1728=2×2×2×2×2×2×3×3×3

So,here we go

$\begin{gathered}\begin{gathered} \sqrt{1728} = \sqrt{2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 3 \times 3 \times 3 } \\ = \sqrt{ {2}^{3} \times {2}^{3} \times {3}^{3} } \\ = 2 \times 2 \times 3 \\ = 12\end{gathered} \end{gathered}$

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