Question

find cuberoot of 729 by solution​

Answer 1

Answer:

An integer is divisible by 9 if and only if the sum of its digits is divisible by 9.

The sum of the digits of 729 is 7 + 2 + 9 = 18 and 18 is divisible by 9 so 729 is divisible by 9.

Answer 2

answer is 729=3×3×3×3×3×3=729=9 ki power 3

Explanation:

clearly,729 is a perfect cube

here will be a using laws of exponent

729 =3 ki power 6 law (a ki power m ×a ki power n )=a ki power m+n

729=3 ki power 2×3(a ki power m×n=a ki power mn )

729 =9 ki power 3

I think I help you