find cubic polynomial whose zeros are 3 , 1/2 and -1
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a+b+c = 3+1/2 -1 = 5/2
Ab+bc+ca= 3/2 -3-1/2 = -1
abc = -3/2
Equation
X^3 - (5/2) x^2 + (-1)x - (-3/2) =0
2x^3 - 5x^2 -x - 3 = 0
Ab+bc+ca= 3/2 -3-1/2 = -1
abc = -3/2
Equation
X^3 - (5/2) x^2 + (-1)x - (-3/2) =0
2x^3 - 5x^2 -x - 3 = 0
brahesh:
thanks bro
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